I haven't tried this, but there is an XPath function that takes xs:date (which is what current-date() returns) and adjusts it to a particular timezone -- or simply removes the timezone portion, which is what you want.
The function is adjust-date-to-timezone( xs:date [,xs:dayTimeDuration]).
Hope this helps,
Sara, technical writer/jackbe
Hi Sara,
The following emml snippet did what I needed:
<assign outputvariable="$currentDateNoTZ"
fromexpr="fn:ISODateFormatExt(adjust-date-to-timezone(current-date(),()),'yyyy-MM-dd',$newpubDateFormat)" />
and gave me a date in the form of dd/MM/yyyy from current-date() where $newpubDateFormat was "dd/MM/yyyy".
The key part of the call to the adjust-date-to-timezone function is to include the empty "()" as the second param. This ensures that the date returned does not include the Time Zone suffix of the date.
Cheers, Innes
Hi guys,
just wondering if this is an error or if I'm doing something wrong.
I tried to use the ISODateFormatExt function to convert the date returned from the XPath function current-date() which is returned in the form 2009-11-12+13:00. If I'm correct, in the ISO format that should be something yyyy-MM-ddZ.
When I tried to convert this to simply dd/MM/yyyy I got the following error:
ERROR [com.jackbe.jbp.jems.client.EMMLPrestoFunctions] - <ISODateFormatExt : Parse ExceptionUnparseable date: "2009-11-12+13:00">
Cheers, Innes (NZ)